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An Interval Timer
(Designing a Printed Circuit Board)
Intro to Eng. II - Module 2
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Appendix A: How the Interval Timer Works
The interval timer has basically 3 different
parts:
These parts are indicated in Figure A1.

Parts (1) and (2) are really not separate but
interact with each other. They are important in determining how
the circuit works so we will consider them in detail.
The Capacitor
The basic time interval that the circuit produces is accomplished by charging a capacitor. A capacitor is a device that can "separate" charge. It consists essentially of two conducting plates separated by an insulator as shown in Figure A2.

A current in the top lead, as shown, deposits
positive charge on the top plate. The current in the bottom lead
(which, at any time, must be equal to the current in the top lead)
removes positive charge from the bottom plate and hence leaves
a negative charge on the bottom plate. The amount of positive
charge on the top plate, at any time, must equal the amount of
negative charge on the bottom plate.
Whenever there is a positive charge on one
plate (and an equal amount of negative charge on the other plate),
there is a voltage across the plates which is proportional to
the magnitude of the charge. This voltage will be a rise from
the negatively charged plate to the positively charged plate.
(The relation between the voltage and charge is: v=Cq where C
is the capacitance of the capacitor. The capacitance of
a capacitor depends primarily on the size of the plates, the distance
between them, and the electrical properties of the insulator between
the plates.)
The unit of capacitance is the "farad".
It turns out a farad is a very large unit indeed. Real world
capacitors that you will encounter usually have values between
10-12 (a "picofarad") to 10-3 farads. A common unit
for capacitance is the "microfarad" which is 10-6 farads.
Charging the Capacitor
The capacitor is placed in the simple circuit
shown in Figure A3. Assume at first that there is no charge on
the capacitor as shown in (a). Since the capacitor voltage is
zero, the battery voltage, VB, all appears across the resistor
R, and a large current is produced. This current starts to charge
up the capacitor by depositing positive charge on the top plate
and removing negative charge from the bottom plate. As charge
accumulates, the capacitor voltage, v, builds up. This voltage
reduces the voltage across the resistor and the current gets smaller.
Finally, after a long time, the capacitor charge will have increased
to the point that the capacitor voltage is equal to the battery
voltage and the current will be zero. We can say that the capacitor
is fully charged.
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| (a) | (b) | (c) |
The way the capacitor voltage looks as the
capacitor charges is shown in Figure A4.

This time function is an "exponential"
function, and it has form given in equation (1):
(1)
where t (tau)
is the "time constant". The exponential function in
Figure A4 has VB=1 and t (tau) =1.
It turns out that the time constant for the
series RC circuit is equal to the product of the resistor's value
times the capacitor's value (t=RC) or (tau=RC).
If R is in ohms and C is in farads, then the unit of the time
constant will be seconds.
A circuit with a small time constant would
charge faster than a circuit with a larger time constant. Figure
A5 shows three exponential functions with different time constants.
Enter in R & C values to see
The 555 Timer
Now let's look at how the 555 timer is connected
to the timing circuit. A portion of the 555 timer is shown in
Figure A6.
The part of the 555 timer which causes the
capacitor to charge and dischargd is basically a switch which
is controlled by an input voltage. In this case, the voltage
across our capacitor is the input voltage which is used to control
the switch.
When the switch is open, the capacitor charges.
The charging circuit is shown in Figure A7(a). (Since the switch
is open, we don't have to show it.)
When the switch is closed, the capacitor is
"shorted out" as shown in Figure A7(b). The voltage
across the capacitor is zero.
So let's see what the switch control portion
of the 555 timer does. The input to the switch control is the
capacitor voltage, so that it is possible to switch between the
charging and discharging circuits when the capacitor voltage reaches
a certain level.
Assuming the capacitor voltage is initially
zero, and the switch is open, then the capacitor will charge up
to the battery voltage (9 volts in our case) exponentially with
a time constant,t (tau),
having the value RC as shown in Figure A8.
The 555 timer switch control is such that when
the capacitor voltage reaches a level which is 2/3 of the battery
voltage (i.e., 6 volts), the switch will close and the capacitor
voltage will then discharge rapidly to zero as shown.
Calculating the Interval Time
The equation for the charging waveform is given
in equation (2)
v = 9(1 - exp[-t/t])
(2)
where t=RC.
Now T can be found from equation (2). T is
the time at which v = 6 volts, so
9exp[-T/t]
= 9 - 6 = 3
from which T = -t
ln(1/3) = 1.098t
or
T = 1.098RC (3)
The Circuit in More Detail
Figure A9 shows the interval timer in more
detail.
In particular the internal structure of the
555 timer is expanded. The portion of the timer called the switch
control above is in reality a flip-flop and two comparators.
A flip-flop is a common electronic circuit that has two stable
states, and the device generally "flips" between them.
The output of the flip flop is "high" (9 volts) or
"low" (0 volts). It is this output that turns on and
off the transistor switch which changes the mode between charging
and discharging the capacitor. The output of the flip-flop is
available on pin 3 of the 555 timer, and it is this signal which
is supplied to the transistor-LED circuit.
Signals to switch the flip-flop are derived
from the two comparators. These devices compare two input signals
and indicate when one particular signal is higher than the other.
Initially, the trigger input, 2, is high, the
flip-flop output is low and the 555 transistor switch is closed
The push button is pressed. When the trigger
input, 2, is below V/3, it causes the flip-flop to be low (0 volts)
and the transistor switch inside the 555 timer to be open. Hence
the capacitor will be start to charge.
The signal which causes the internal switch
inside the 555 timer to open so that the capacitor can charge,
is used to control the 2N2222 transistor switch so that the LED
lights during the time that the capacitor is charging.
MATLAB Interactive Demo
calculated time response.

Figure A5. Three Time Constants




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Student Guide ToC
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Appendix B
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Timer Main Page
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EASNE Page